5p^2+10p-175=0

Solution for 5p^2+10p-175=0 equation:

5p^2+10p-175=0

a = 5; b = 10; c = -175;
Δ = b2-4ac
Δ = 102-4·5·(-175)
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-60}{2*5}=\frac{-70}{10}
=-7
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+60}{2*5}=\frac{50}{10}
=5
$